Question

Example 3 :Find the zeroes of the polynomial rº - 3 and verify the relationship
between the zeroes and the coefficients.
Solution Recall the identity g2_h2 = (-ha+h). Using it, we can write:​

Answer 1

$\rm\bf\underline{Question:}$

x²-3 = 0

x² = 3

x = ±√3

Therefore, the zeroes of the given polynomial are √3 and -√3.

Relationship between the zeroes and coefficients :-

Sum of zeroes = √3+(-√3) = √3-√3

= 0 = -x coefficient/x² coefficient

Product of zeroes = (√3)(-√3)

= -(√3)² = -3/1 = constant/x² coefficient

Hope it helps

Answer 2

$\large \tt \pink {answer❤}$

x²-3 = 0

x² = 3

x = ±√3

Therefore, the zeroes of the given polynomial are √3 and -√3.

Relationship between the zeroes and coefficients :-

Sum of zeroes = √3+(-√3) = √3-√3

= 0 = -x coefficient/x² coefficient

Product of zeroes = (√3)(-√3)

= -(√3)² = -3/1 = constant/x² coefficient