Question

Example 4.3 An object is projected with a velocity of 30 ms
at an angle of 60° with the horizontal. Determine the horizontal
range covered by the object.​

Answer 1

Answer:

79.4

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Answer 2

Answer:

R=usin2theta/g

 =30 x sin120/10   (g=10 m/s^2)

=3 x 2sin60cos60

=3 x 2 x $\sqrt{3}$/2 x 1/$\sqrt{2}$

=3 x $\sqrt{3}$/$\sqrt{2}$ m

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