Question

Example 5 : A water sample contains following impurities: Mg(HCO3)2 = 292 mg/L, CaCl2 =
166.5 ppm, SiO2 = 5 ppm, Calculate the volume of EDTA solution (0.1 N) required to titrate 50
mL of the water sample before boiling and after boiling-filtering.
(Ans: 1.5 mL)​

Answer 1

Answer:

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Answer 2

Given:

A water sample contains following impurities: Mg(HCO3)2 = 292 mg/L, CaCl2 =  166.5 ppm, SiO2 = 5 ppm

To find:

Calculate the volume of EDTA solution (0.1 N) required to titrate 50  mL of the water sample before boiling and after boiling-filtering.

Solution:

From given, we have,

Mg(HCO₃)₂ = 292 mg/L, CaCl₂ =  166.5 ppm, SiO₂ = 5 ppm

50  mL of the water = 0.05 l

so, we have,

m(CaCl₂) = 166.5 × 0.05 = 8.325 mg  = 0.008325 g

m(Mg(HCO₃)₂) = 292 × 0.05 = 14.6 mg  = 0.0146 g

ν = ν(Mg(HCO₃)₂) + ν(CaCl₂) = 0.0146/146  +  0.008325/111 = 0.000175 mol

V(EDTA)= ν × 1000/H = 1.75 ml

Therefore, the volume of EDTA solution (0.1 N) required to titrate 50  mL of the water sample before boiling and after boiling-filtering. is 1.75 ml