Question

Example 5 : Find the roots of the quadratic equation 3x
$3x {}^{2} - 2 \sqrt{6}x + 2 = 0$
- 2/6x+2 = 0
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Answer 1

Step-by-step explanation:

$3 {x}^{2} - 2 \sqrt{6} x + 2 = 0$

$= > {( \sqrt{3} x)}^{2} - 2 \times \sqrt{3} x \times \sqrt{2} + {( \sqrt{2} )}^{2} = 0$

$= > {( \sqrt{3} x - \sqrt{2} )}^{2} = 0$

$\sqrt{3} x - \sqrt{2} = 0$

$= > x = \frac{ \sqrt{2} }{ \sqrt{3} }$

$= > x = \sqrt{ \frac{2}{3} }$