Question

Example 6.5 : A closed pipe and an open
pipe have the same length. Show that
no mode of the closed pipe has the same
wavelength as any mode of the open pipe.​

Answer 1

Answer:

Let f be the length of the pipe and v the speed of the sound. The frequency of the open organ pipe of n

th

overtone is ,

f

1

=(n+1)

2l

v

And frequency of closed organ pipe of n

th

overtone is,

f

2

=(2n+1)

4l

v

The desired ratio is thus,

f

2

f

1

=

2n+1

2(n+1)