Question

Example 6 : In an isosceles triangle ABC with AB = AC, D and E are points on BC
such that BE = CD (see Fig. 7.29). Show that AD = AE.
Solution - In A ABD and A​

Answer 1

Answer:

Given ABC is an isosceles triangle with AB=AC .D and E are the point on BC such that BE=CD

Step-by-step explanation:

Given AB=AC

∴∠ABD=∠ACE (opposite angle of sides of a triangle ) .

Given BE=CD

Then BE−DE=CD−DE

ORBC=CE....

In ΔABD  and ΔACE

∠ABD=∠ACE  (  From 1)

BC=CE (from 2)

AB=AC ( GIven)

∴ΔABD≅ΔACE

So AD=AE