Question

Example 8.5 A train starting from rest
attains a velocity of 72 km h-l in
5 ininutes. Assuming that the
acceleration is uniform, find (i) the
acceleration and (ii) the distance
travelled by the train for attaining this
velocity.​

Answer 1

Answer:

u=0 m/s

v=72 km/hr

v=20 m/s

t= 300 sec

a= v-u÷t

a=1/15 m/s

2as=v×v-u×u

s=3km

Answer 2

Answer:

a=1/15m/s^2

d=6000m =6km

Step-by-step explanation:

1 acceleration=v-u/t ,train starting from rest then u=0, v=72km/hr convert into m/s then 72*5/18=20m/s..then time is in min change into sec 5 min =300sec then Applying formula a=20-0/300=1/15m/sec^2

2 distance=speed*time =20*300=6000m =6km..ans