Example 8.7 The brakes applied to a car
produce an acceleration of 6 m sº in
the opposite direction to the motion. If
the car takes 2 s to stop after the
application of brakes, calculate the
distance it travels during this time.
Answers
Answered by
2
Answer:
12m
Explanation:
here
a=-6
t=2
v=0
s❓
v=u + at
therefore
0= u + (-6×2)
u= 12 mper s
using second law,
s= ut+ 1/2 at^2
=12×2+1/2×(-6)×4
= 24-12
=12m
Answered by
1
Answer:
your answer is 12m please mark as brainlist please
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