Question

Example 8 : In Fig. 6.39, the sides AB and AC of
AABC are produced to points E and D respectively.
If bisectors BO and CO of Z CBE and Z BCD
respectively meet at point o, then prove that
1
BOC = 90° ZBAC.
2
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Answer 1

Answer:

$\huge\underbrace\bold\pink{AnswEr}$

If bisectors BO and CO of ∠CBE and ∠BCD respectively meet at point O, then prove that ∠BOC ... BO is the bisector of ∠ CBE So, ∠ CBO = ∠ EBO = 1/2 ∠ CBE Similarly, CO is the bisecto .