Example 9.2 A copper wire of length 2.2
m and a steel wire of length 1.6 m, both of
diameter 3.0 mm. are connected end to end.
When stretched by a load, the net
elongation is found to be 0.70 mm. Obtain
the load applied
der
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Answer:
Given that,
Length of the copper wirel1=2.2m
Length of the steel wire l2=1.6m
Elongation in length△l=0.5.mm
=0.5×10−3m
Radius of theCu wire r1=1.5×10−3m
Y1=1.1×1011N/m2
Y2=2.0×1011N/m2
Let F be the stretching force in both the wires then,
for Cu wire, Y1=πr12F×△l1l1
⇒F=l1Y1πr12×△l1
=2.21.1×10−11×722×(1.5×10−3)
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