Question

Example 9.2 A copper wire of length 2.2
m and a steel wire of length 1.6 m, both of
diameter 3.0 mm. are connected end to end.
When stretched by a load, the net
elongation is found to be 0.70 mm. Obtain
the load applied
der​

Answer 1

Answer:

Given that,

Length of the copper wirel1=2.2m

Length of the steel wire l2=1.6m

Elongation in length△l=0.5.mm

                           =0.5×10−3m

 Radius of theCu wire r1=1.5×10−3m

Y1=1.1×1011N/m2

Y2=2.0×1011N/m2

Let F be the stretching force in both the wires then,

for Cu wire, Y1=πr12F×△l1l1

⇒F=l1Y1πr12×△l1

=2.21.1×10−11×722×(1.5×10−3)