Example 9. Position of moving particle change
with time t according to the following relation
* x=t^2+3
where x is in metre and is in second .
Find :
() Position of particle at
t= 0 sec and t=3sec
sandrs
(ii) Average velocity between time interval t=2 to t=4
(Velocity of particle at t=5s.
Answers
Answered by
6
Answer:
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Explanation:
t=
x+3
Velocity=0
t=x
1/2
+3
t−3=x
1/2
(t−3)
2
=x
dt
dx
=2(t−3)
For v=0
o=2t−6
t=3s
Answered by
4
Answer:
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Do some reading also means to take up reading as a hobby or even for general knowledge.
Hope it helps.
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