Question

EXAMPLE - Three resistance are in parallel. The current in the first resistor is 0.1 A. The power dissipation in the second resistor is 3 watts. The voltage drop across the third resistor is 100 volts. Determine the values of resistor and total resistance, if total current is 0.2 A​/please answer this question it's urgent I will mark you as branliest​

Answer 1

Answer:

r2=10/3k ohm , r3=1k ohm, r1=1.03k ohm

Explanation:

total resis. =10/16

Answer 2

Answer:

First, we use Ohm's law ( V = I × R ), to find the current through the resistor. The voltage across the resistor is V = 9 V. The resistance of the resistor is R = 100 Ω. Then, we can use the power rule ( P = I × V ), to find the power dissipated by the resistor.