EXAMPLES
EXAMPLE 6. A body starts from rest and acquires a velocity of 12 m s' in 5
Calculate the acceleration and the distance travelled.
OTITION til
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Answer:
acceleration = 2.4m/s2 distance travelled=30m
Step-by-step explanation:
Since the body started from rest; u=0
From equations of motion we know that..
v = u+at
Here u=0, t=5 v=12
By substituting
12=0+a(5)
a=12/5=2.4
DISTANCE:
We know that
s=ut+1/2at^2
Here, u=0 t=5 a=12/5
By substituting,
s=1/2(2.4) (5)^2
Therefore,
S= 30m
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