Question

EXAMPLES FOR PRACTICE-3
In the figure, find the value of 'r'.
Р
X
Q=100°
R=50​

Answer 1

Answer:

ANSWER

∠TQS=180−∠PQT−∠SQR=180–70–50=60

WKT OQ⊥PR

∠OQS=90−∠SQR=90–50=40

In △OQS

∠OQA=∠OSQ=40

∠QOS=180−∠OQS−∠OSQ=180–40–40=100

Now,

∠QTS=

2

1

∠QOS because angle made but n arc at the center is twice the angle made by the arc on any point of circle

∠QTS=

2

100

=50

In △QTS

∠TSQ=180–50−60=70

∠TSO+∠OSQ=70

x=70–40=30

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