examples for substitution and elimination method
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subsitution:
equation 1: x=1
equation 2: x + y = 2
substitute 1 in 2
1 + y = 2
y = 2 - 1 (when 1 goes that side it becomes negative)
y = 1
elimination:
eq 1 : x + y -2 = 0
eq 2 : x - y - 4 = 0
if we eliminate y we get:
x -2 = 0
x - 4 = 0
add both,we get
2x -6 = 0
2x = 6
x = 3
equation 1: x=1
equation 2: x + y = 2
substitute 1 in 2
1 + y = 2
y = 2 - 1 (when 1 goes that side it becomes negative)
y = 1
elimination:
eq 1 : x + y -2 = 0
eq 2 : x - y - 4 = 0
if we eliminate y we get:
x -2 = 0
x - 4 = 0
add both,we get
2x -6 = 0
2x = 6
x = 3
Answered by
1
Substitution:-
Step 1: 5x + 3y = 26 [Equation 1.]
Step 2: x - 3y = 4 [Equation 2.]
Step 3: x = 3y + 4 [Rearrange equation 2.]
Step 4: 5(3y + 4) + 3y = 26 [Substitute the values.]
Step 5: 18y + 20 = 26 [Group the like terms.]
Step 6: 18y = 6 [Subtracting 20 from the two sides of the equation.]
Step 7: [Divide throughout by 18.]
Step 8: [Substitute the values.]
Step 9: x = 5 [Simplify.]
Step 10: The solution for the linear system is .
Step 1: 5x + 3y = 26 [Equation 1.]
Step 2: x - 3y = 4 [Equation 2.]
Step 3: x = 3y + 4 [Rearrange equation 2.]
Step 4: 5(3y + 4) + 3y = 26 [Substitute the values.]
Step 5: 18y + 20 = 26 [Group the like terms.]
Step 6: 18y = 6 [Subtracting 20 from the two sides of the equation.]
Step 7: [Divide throughout by 18.]
Step 8: [Substitute the values.]
Step 9: x = 5 [Simplify.]
Step 10: The solution for the linear system is .
Anonymous:
i only know about substitution
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