Examples of chemical potential and gibbs free energy
Answers
Answered by
0
Examples of matter containing chemical energy include: coal - combustion reaction converts chemical energy into light and heat. wood - combustion reaction converts chemical energy into light and heat. petroleum - can be burned to release light and heat or changed into another form of chemical energy, such as gasoline.
Gibbs free energy, or delta G is the enthalpychange of a reaction, delta H minus the entropyof the reaction system multiplied by product of temperature (t)
The equation is as follows:
G=H−TS
In terms of examples, I am unsure on whether you meant real life examples or calculation examples, therefore I will provide both down below.
Gibbs Free Energy is simply just an equation that is used to calculate if a reaction is spontaneous or not. An example problem would be:
Estimate the temperature where ΔG = 0 for the following reaction: (Given: ΔH = -176 kJ and ΔS = -284.5 J/K) CAUTION: Beware of units.
NH3(g) + HCl(g) ---> NH4Cl(s)
Using the equation above, we seperate T to be on one side, giving us (G+H)/S = T. Then we subsitute the values in the equation. As how the question states it, Beware of units!
1 J = 1000kJ, therefore -284.5 J/K/1000 gives us -0.2845 kJ.
By subsituting this value in the equation for S, you should be able to obtain the answer 619K.
Gibbs free energy, or delta G is the enthalpychange of a reaction, delta H minus the entropyof the reaction system multiplied by product of temperature (t)
The equation is as follows:
G=H−TS
In terms of examples, I am unsure on whether you meant real life examples or calculation examples, therefore I will provide both down below.
Gibbs Free Energy is simply just an equation that is used to calculate if a reaction is spontaneous or not. An example problem would be:
Estimate the temperature where ΔG = 0 for the following reaction: (Given: ΔH = -176 kJ and ΔS = -284.5 J/K) CAUTION: Beware of units.
NH3(g) + HCl(g) ---> NH4Cl(s)
Using the equation above, we seperate T to be on one side, giving us (G+H)/S = T. Then we subsitute the values in the equation. As how the question states it, Beware of units!
1 J = 1000kJ, therefore -284.5 J/K/1000 gives us -0.2845 kJ.
By subsituting this value in the equation for S, you should be able to obtain the answer 619K.
Attachments:
Similar questions