Question

examples on finding the position velocity and acceleration using the formulae of differentiation​

Answer 1

Answer:

HI BUDDY! HERE IS YOUR ANSWER.

FORMULA OF DISTANCE = SPEED × TIME

FORMULA OF SPEED = $\frac{DISTANCE}{TIME}$

FORMULA OF AVERAGE SPEED = $\frac{TOTAL DISTANCE}{TOTAL TIME}$

FORMULA OF DISPLACEMENT = VELOCITY × TIME

FORMULA OF VELOCITY =  $\frac{DISPLACEMENT}{TIME}$

FORMULA OF AVERAGE VELOCITY = $\frac{INITIAL VELOCITY + FINAL VELOCITY}{2}$

FORMULA OF ACCELERATION = $\frac{INITIAL VELOCITY + FINAL VELOCITY}{TIME}$

IMPORMANT EQUATIONS :-

V = U + AT

S = UT + $\frac{1}{2}$ A$T^{2}$

2 AS = $V^{2}$ - $U^{2}$

HOPE IT HELPS YOU!

Answer 2

Answer:

• Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity. As velocity is an example of vector, it has direction and magnitude. ... a change in both speed and direction (from 34 km/h East to 12 km/h West)