the distance between two stations is 402 km that two the train starts simultaneously from the station in opposite direction the speed of one of them is greater than that of the other by 20 km per hour if the speed of slower train is 50 km per hour after how many hours will they meet together
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Let r be the speed of first train.
And r+5 be the speed of other train.
The distance first train travels in 2 hours is =2r
The distance other train travels in 2 hours is (r+5)×2=2(r+5)
Now we know that the distance the first train travels (2r) plus the distance the other train travels 2(r+5) equals 340−30=310.
So, 2r+2(r+5)=310
⇒2r+2r+10=310
⇒4r=300
⇒r=75
Thus, speed of first train is 75 mph.
Therefore, the speed of other train is r+5=75+5=80 mph.
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