Excess H2S is bubbled through a 0.1 M, IL solution
of Cuci, (Cuci, + H2S → CuS + 2HCI) and 1 L of
water is added to the solution after the reaction is
complete.
Answers
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0
Answer:
Explanation:
moles of Cu2+ = 1.0 X 0.1 = 0.1
mol Cu2+ = 0.1 X 2 = 0.2 mol H
weight of CuS = 0.1 X 95.5 = 9.55g
concentration of H = 0.2/1.0 = 0.2 M
hence
1)9.55 g of cuS is produced
2) concentration of H ions is 0.2 M
please brainliest here
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