Excess pressure inside a liquid drop where surface tension is t and radius r
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Step-by-step explanation:
As we know that, the force due to surface tension act normal to the surface in inward direction on the molecules of a liquid drop. For an equilibrium of the drop, these must exist excess pressure insie it. Let R be the radius of a drop and dR be the increase in its radius by small amount due to excess pressure.
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It has no component perpendicular to the horizontal surface. As a result, there is no pressure difference between the liquid side and the vapour side. ... Thus, there is always an excess of pressure on the concave side of a curved liquid surface over the pressure on its convex side due to surface tension.
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