Question

EXERC
)
Find the values of
i) sin 15° ii)​

Answer 1

Answer:

Given below

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Answer 2

Answer:

$\boxed{\text{sin}(15^{\circ})=\dfrac{\sqrt{3}-1}{2\sqrt{2}}}$

Step-by-step explanation:

The given expression is as follows:

$\boxed{\text{sin}(15^{\circ})}$

Solve the given expression as shown below:

$\begin{aligned}\text{sin}(15^{\circ})&=\text{sin}(45^{\circ}-30^{\circ})\\&=\text{sin}(45^{\circ})\cdot \text{cos}{30^{\circ}}-\text{cos}(45^{\circ})\cdot \text{sin}{30^{\circ}}\\&=\left(\dfrac{1}{\sqrt2}\right)\cdot \left(\dfrac{\sqrt3}{2}\right)-\left(\dfrac{1}{\sqrt2}\right)\cdot \left(\dfrac{1}{2}\right)\\&=\dfrac{\sqrt{3}-1}{2\sqrt{2}}\end{aligned}$

Therefore, the value of the given expression is $\boxed{\dfrac{\sqrt{3}-1}{2\sqrt{2}}}$.