Math, asked by paridhibhatt, 9 months ago

EXERCISE 13.2
Assume re = 22, unless stated otherwise,
The curved surface area of a right circular cylinder of height 14 cm is 88 cm². Find the
diameter of the base of the cylinder.
It is required to make a closed cylindrical tank of height 1 m and base diameter 140 cm
from a metal sheet. How many square metres of the sheet are required for the same?
A metal pipe is 77 cm long. The inner diameter of a cross
section is 4 cm, the outer diameter being 4.4 cm
(see Fig. 13.11). Find its
6) inner curved surface area,
(ii) outer curved surface area,
(iii) total surface area.​

Answers

Answered by hanshraj26
6

Answer:

Assume unless stated otherwise

1. The curved surface area of a right circular cylinder of height 14 cm is 88 cm2. Find the diameter of the base of the cylinder.

Ans. Given: Height of cylinder = 14 cm, Curved Surface Area = 88 cm2

Let radius of base of right circular cylinder = cm

= 88

1 cm

Diameter of the base of the cylinder = = 2 x 1 = 2 cm

2. It is required to make a closed cylindrical tank of height 1 m and base diameter 140 cm from a metal sheet. How many square meters of the sheet are required for the same?

Ans. Given: Diameter = 140 cm

Radius = 70 cm = 0.7 m

Height of the cylinder = 1 m

Total Surface Area of the cylinder

=

=

= 2 x 22 x 0.1 x 1.7 = 7.48 m2

Hence 7.48 m2 metal sheet is required to make the close cylindrical tank.

3. A metal pipe is 77 cm long. The inner diameter of a cross section is 4 cm, the outer diameter being 4.4 cm. [See fig.]. Find its:

(i) Inner curved surface area

(ii) Outer curved surface area

(iii) Total surface area

Ans. (i) Length of the pipe = 77 cm, Inner diameter of cross-section = 4 cm

Inner radius of cross-section = 2 cm

Inner curved surface area of pipe = =

= 2 x 22 x 2 x 11 = 968 cm2

(ii) Length of pipe = 77 cm, Outer diameter of pipe = 4.4 cm

Outer radius of the pipe = 2.2 cm

Outer surface area of the pipe =

=

= 44 x 2.2 x 11 = 1064.8 cm2

(iii) Now there are two circles of radii 2 cm and 2.2 cm at both the ends of the pipe.

Area of two edges of the pipe = 2 (Area of outer circle – area of inner circle)

= =

= =

= = 5.28 cm2

Total surface area of pipe

= Inner curved surface area + Outer curved surface area + Area of two edges

= 968 + 1064.8 + 5.28 = 2038.08 cm2

Step-by-step explanation:

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Answered by chrisekka540
0

Answer:

Let the radius and height of the cylinder be 'r' and 'h' respectively.

Curved Surface Area of a right circular cylinder = 2 π r h

Diameter = 2 × radius

Height of the cylinder, h = 14 cm

CSA of the cylinder = 88 cm²

2 π r h = 88 cm²

2 × 22/7 × r × 14 cm = 88 cm²

r = (88 cm² × 7) / (2 × 22 × 14) cm

= 1 cm

Diameter = 2 × radius

= 2 × 1 cm

= 2 cm

Thus, the diameter of the base of the cylinder is 2 cm.

Step-by-step explanation:

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