Question

EXERCISE 171
LEVEL-1
1. Find the area of a triangle whose sides are respectively 150 cm, 120 cm and 200​

Answer 1

Answer:

we know that Area of triangle=

$\sqrt{s(s - a)(s - b)(s - c)}$

s = semi perimeter of triangle = (a+b+c)/2

s = (150+120+200)/2 = 470/2 = 235.

so Area of triangle=

$\sqrt{235 \times (235 - 150)(235 - 120)(235 - 200} =$

$\sqrt{235 \times 85 \times 115 \times 35} = 8966.56986 \: {cm}^{2} \: ans.$

Answer 2

Answer:

same answer as above। nice solution