Question

EXERCISE 3.3
1. Solve the following pair of linear equations by the substitution method.
(1) x+y=14
(m) s-1=3
x-y=4
(i) 3x-y-3
3 2
(iv) 02x+3y13
04x+0.5y = 23
3x S-2
9- 3y=9 ans
(v) Vzx+√3 y0 Sex (m 2 su
√3x - √&y=0
13
3 2 6
plzplzplzplzplz give the answer​

Answer 1

Answer:

2

Step-by-step explanation:

2x-2=6

12-3/=2

14*5/=3

Answer 2

Step-by-step explanation:

(i) Given,

x + y = 14 and x – y = 4 are the two equations.

From 1st equation, we get,

x = 14 – y

Now, substitute the value of x in second equation to get,

(14 – y) – y = 4

14 – 2y = 4

2y = 10

Or y = 5

By the value of y, we can now find the exact value of x;

∵ x = 14 – y

∴ x = 14 – 5

Or x = 9

hope it helped you !!:)