Math, asked by anithaeva333, 6 months ago


EXERCISE 3.6
Using prime factorization method, find the HCF of the following numbers:
(a) 60 and 72
(b) 72 and 144
(e) 40, 48 and 72
(1) 144, 180 and 192 please send answer photo for all questions please please please please please please please please ​

Answers

Answered by Anonymous
9

Answer:

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Step-by-step explanation:

The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

The factors of 72 are: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

Then the highest common factor is 12.

________________________________

The factors of 72 are: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

The factors of 144 are: 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 36, 48, 72, 144

Then the highest common factor is 72.

________________________________

The factors of 3 are: 1, 3

The factors of 192 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 64, 96, 192

The factors of 14280 are: 1, 2, 3, 4, 5, 6, 7, 8, 10, 12, 14, 15, 17, 20, 21, 24, 28, 30, 34, 35, 40, 42, 51, 56, 60, 68, 70, 84, 85, 102, 105, 119, 120, 136, 140, 168, 170, 204, 210, 238, 255, 280, 340, 357, 408, 420, 476, 510, 595, 680, 714, 840, 952, 1020, 1190, 1428, 1785, 2040, 2380, 2856, 3570, 4760, 7140, 14280

Then the greatest common factor is 3.

_______________________________

The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24

The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36

The factors of 90 are: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

Then the greatest common factor is 6.

________________________________

The factors of 40 are: 1, 2, 4, 5, 8, 10, 20, 40

The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

The factors of 72 are: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

Then the highest common factor is 8.

________________________________The factors of 144 are: 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 36, 48, 72, 144

The factors of 180 are: 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, 180

The factors of 192 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 64, 96, 192

Then the highest common factor is 12.

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