EXERCISE 3.7 (Optional)
1. The ages of two friends Ani and Biju differ by 3 years. Ani's father Dharam
as Ami and Biju is twice as old as his sister Cathy. The ages of Cathy and
by 30 years. Find the ages of Ani and Biju.
shall be become twice a
Answers
MATHS
The ages of two friends Ani and Biju differ by 3 years. Ani's father Dharam is twice as old as Ani and Biju is twice as old as his sister Cathy. The ages of Cathy and Dharam differ by 30 years. Find the ages of Ani and Biju.
October 15, 2019
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Manita Dabbara
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ANSWER
Let the age of Ani and Biju be x and y respectively.
Then according to the question-
x−y=3..........(i)
Dharam is twice the age of Ani
Hence, age of Dharam =2x
Age of Cathy is half the age of Biju
Then age of Cathy =
2
y
Then according to the question
2x−
2
y
=30
⇒4x−y=60......(ii)
Subtracting (ii) from (i)
⇒x−y−4x+y=3−60
⇒−3x=−57
⇒x=
−3
−57
=19
Substitute the vale of x in (i)
⇒19−y=3
⇒−y=−16
⇒y=16
∴ Age of Ani =19 years and age of Biju =16 years.
Answer:
Let the ages of Ani be A
Let the age of Biju be B
Hence, the age of Dharam = 2 x A = 2A yrs.
The age of Biju sister Ani B/2 yrs
As per the given conditions will solve
Case (i)
When Ani is older than that of Biju
A – B = 3 – – – – – – – – (1) {older by 3 years}
2A−B/2 = 30
4A – B = 60 – – – – – – – – – – – (2)
By subtracting the equations (1) and (2) we get,
3A = 60 – 3 = 57
A = 57/3 = 19
The age of Ani = 19 yrs
The age of Biju is 19 – 3 = 16 yrs.
Case (ii)
When Biju is older than Ani,
B – A = 3 – – – – – – – – – (1) {older by 3 years}
2A − B/2 = 30
4A – B = 60 – – – – – – – – – (2)
Adding the equation (1) and (2) we get,
3A = 63
A = 21
Answer
The age of Ani is 21 yrs
The age of Biju is 21 + 3 = 24 yrs.