Math, asked by hs77289898, 9 months ago

EXERCISE 3.7 (Optional)
1. The ages of two friends Ani and Biju differ by 3 years. Ani's father Dharam
as Ami and Biju is twice as old as his sister Cathy. The ages of Cathy and
by 30 years. Find the ages of Ani and Biju.
shall be become twice a​

Answers

Answered by venesha11
3

MATHS

The ages of two friends Ani and Biju differ by 3 years. Ani's father Dharam is twice as old as Ani and Biju is twice as old as his sister Cathy. The ages of Cathy and Dharam differ by 30 years. Find the ages of Ani and Biju.

October 15, 2019

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Manita Dabbara

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ANSWER

Let the age of Ani and Biju be x and y respectively.

Then according to the question-

x−y=3..........(i)

Dharam is twice the age of Ani

Hence, age of Dharam =2x

Age of Cathy is half the age of Biju

Then age of Cathy =

2

y

Then according to the question

2x−

2

y

=30

⇒4x−y=60......(ii)

Subtracting (ii) from (i)

⇒x−y−4x+y=3−60

⇒−3x=−57

⇒x=

−3

−57

=19

Substitute the vale of x in (i)

⇒19−y=3

⇒−y=−16

⇒y=16

∴ Age of Ani =19 years and age of Biju =16 years.

Answered by MysteriousAryan
0

Answer:

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Let the ages of Ani be A

Let the age of Biju be B

Hence, the age of Dharam = 2 x A = 2A yrs.

The age of Biju sister Ani B/2 yrs

As per the given conditions will solve

Case (i)

When Ani is older than that of Biju

A – B = 3 – – – – – – – – (1) {older by 3 years}

2A−B/2 = 30

4A – B = 60 – – – – – – – – – – – (2)

By subtracting the equations (1) and (2) we get,

3A = 60 – 3 = 57

A = 57/3 = 19

The age of Ani = 19 yrs

The age of Biju is 19 – 3 = 16 yrs.

Case (ii)

When Biju is older than Ani,

B – A = 3 – – – – – – – – – (1) {older by 3 years}

2A − B/2 = 30

4A – B = 60 – – – – – – – – – (2)

Adding the equation (1) and (2) we get,

3A = 63

A = 21

Answer

The age of Ani is 21 yrs

The age of Biju is 21 + 3 = 24 yrs.

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