Question

Exercise 3.8
1. Find the smallest four-digit number which is divisible by 18, 24 and 32
2. Four bells ring at intervals of 3, 7, 12 and 14 seconds respectively. At what times will they ring
together if they start ringing at 7 a.m.?
3. Find the least natural number which when divided by 25, 40 and 60 leaves a remainder
4, Find the largest number which is the factor of 2261, 3059and 3325
Mathematics-6​

Answer 1

Answer:

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Answer 2

Answer:

1. 288 is divisible by 18, 24 and 32, 1152 is also divisible by all these numbers. Therefore, 1152 is the smallest four digit number divisible by 18, 24 and 32.

2. 1hr 24 minutes. Hope this helps! To find the answer, we need to find the LCM of 3, 7, 12, 14

3. LCM of 25, 40 & 60 = 2*2*2*5*5*3 = 8*25*3 = 200*3 = 600. 600 perfectly divides the 3 numbers and leaves the remainder as 0. So, 600+8 = 608 is the smallest number which leaves remainder 8 when divided by 20, 40 & 60

4. Highest common factor is the highest number which can divide to the given numbers. So, HCF[2261, 3059, 3325] = 133.

hope this will help you make me as brainliest!!!!!!!