Math, asked by Sophie183, 10 months ago

EXERCISE - 5.1
Check whether the following are quadratic equations :
i. (x + 1)2 = 2(x – 3)
ii. x² – 2x = (-2) (3 – x)

Answers

Answered by Ayeshah10
9

Answer:

(x + 1) 2 = 2(x - 3) \\  \\ x2 + 1 + 2x = 2x - 6 \\  \\ x2 + 1 + 2x - 2x + 6 = 0 \\  \\ x2 + 7 = 0 \\  \\ given \: equation \: is \: quadratic \: equation.

given equation is quadratic equation.

x2 - 2x = ( - 2)(3 - x). \\  \\  x2 - 2x =  - 6 + 2x \\  \\ x2 - 2x - 2x + 6 = 0 \\  \\ x2 - 4x + 6 = 0. \\  \\ it \: is \: a \: quadratic \: equation

my answer is correct.

so please mark as brainliest

Answered by Anonymous
17

\sf\large\pink{\underline{\underline{ \: Question\:1 \: }}} \\

Given:

  • (x + 1)² = 2(x – 3)

Solution:

By using the formula for (a+b)² = a²+2ab+b²

⇒ x² + 2x + 1 = 2x – 6

⇒ x² + 7 = 0

Since the above equation is in the form of ax² + bx + c = 0.

Therefore, the given equation is quadratic equation.

 \\ \sf\large\pink{\underline{\underline{ \: Question\:2 \: }}} \\

Given:

x² – 2x = (–2) (3 – x)

By using the formula for (a+b)² = a²+2ab+b²

⇒ x² – 2x = -6 + 2x

⇒ x² – 4x + 6 = 0

Since the above equation is in the form of ax² + bx + c = 0.

Therefore, the given equation is quadratic equation.

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