EXERCISE 7.6
Find the quotient:
1. 7.488 = 24
2. 61.92 - 12
3. 41.28 - 12
4. 3.366 11
5. 3.042 - 13
6. 345.2:8
7. 78.89 +23
8. 758.16 - 18
9. 3.23 : 5
Answers
Solutions:
(a) 2 / 3 + 1/ 7
Taking LCM
[(2 × 7) + (1 × 3)] / 21
= (14 + 3) / 21
= 17 / 21
(b) 3 / 10 + 7 / 15
Taking LCM 30
= [(3 × 3) + (7 × 2)] / 30
= (9 + 14) / 30
= 23 / 30
(c) 4 / 9 + 2/ 7
Taking LCM 63
= [(4 × 7) + (2 × 9)] / 63
= (28 + 18) / 63
= 46 / 63
(d) 5 / 7 + 1 / 3
Taking LCM 21
= [(5 × 3) + (1 × 7)] / 21
= (15 + 7) / 21
= 22 / 21
(e) 2 / 5 + 1 / 6
Taking LCM 30
= [(2 × 6) + (1 × 5)] / 30
= (12 + 5) / 30
= 17 / 30
(f) 4 / 5 + 2 / 3
Taking LCM 15
= [(4 × 3) + (2 × 5)] / 15
= (12 + 10) / 15
= 22 / 15
(g) 3 / 4 – 1 / 3
Taking LCM 12
= [(3 × 3) – (1 × 4)] / 12
= (9 – 4) / 12
= 5 / 12
(h) 5 / 6 – 1 / 3
Taking LCM 6
= [(5 × 1) – (1 × 2)] / 6
= (5 – 2) / 6
= 3 / 6
= 1 / 2
(i) 2 / 3 + 3 / 4 + 1 / 2
Taking LCM 12
= [(2 × 4) + (3 × 3) + (1 × 6)] / 12
= (8 + 9 + 6) / 12
= 23 / 12
(j) 1 / 2 + 1 / 3 + 1 / 6
Taking LCM 6
= [(1 × 3) + (1 × 2) + (1 × 1)] / 6
= (3 + 2 + 1) / 6
= 6 / 6
= 1
(k) 
= [(3 × 1) + 1] / 3 + [(3 × 3) + 2] / 3
= (3 + 1) / 3 + (9 + 2) / 3
= 4/ 3 + 11 / 3
= (4 + 11) / 3
= 15 / 3
= 5
(l) 
= [(3 × 4) + 2] / 3 + [(3 × 4) + 1] / 4
= 14 / 3 + 13 / 4
= [(14 × 4) + (13 × 3)] / 12
= (56 + 39) / 12
= 95 / 12
(m) 16 / 5 – 7 / 5
= (16 – 7) / 5
= 9 / 5
(n) 4 /3 – 1 / 2
Taking LCM 6
= [(4 × 2) – (1 × 3)] / 6
= (8 – 3) /6
= 5 / 6
2. Sarita bought 2 / 5 metre of ribbon and Lalita 3 /4 metre of ribbon. What is the total length of the ribbon they bought?
Solutions:
Ribbon length bought by Sarita = 2 / 5 metre
Ribbon length bought by Lalita = 3 / 4 metre
Total length of the ribbon bought by both of them = 2 / 5 + 3 / 4
Taking LCM 20
= [(2 × 4) + (3 × 5)] / 20
= (8 + 15) / 20
= 23 / 20 metre
∴ Total length of the ribbon bought by both Sarita and Lalita is 23 / 20 metre
3. Naina was given  piece of cake and Najma was given  piece of cake. Find the total amount of cake was given to both of them.
Solutions:
Fraction of cake Naina got =
= 3 / 2
Fraction of cake Najma got =
= 4 / 3
Total amount of cake given to both of them = 3 / 2 + 4 / 3
= [(3 × 3) + (4 × 2)] / 6
= (9 + 8) / 6
= 17 / 6
=
4. Fill in the boxes:
(a) ▯ – 5 / 8 = 1 / 4
(b) ▯ – 1 / 5 = 1 / 2
(c) 1 / 2 – ▯ = 1 / 6
Solutions:
(a) ▯ – 5 / 8 = 1 / 4
▯ = 1 / 4 + 5 / 8
▯ = [(1 × 2 + 5)] / 8
▯ = 7 / 8
(b) ▯ – 1 / 5 = 1 / 2
▯ = 1 / 2 + 1 / 5
▯ = [(1 × 5) + (1 × 2)] / 10
▯ = (5 + 2) / 10
▯ = 7 / 10
(c) 1 / 2 – ▯ = 1 / 6
▯ = 1 / 2 – 1 / 6
▯ = [(1 × 3) – (1 × 1)] / 6
▯ = (3 – 1) / 6
▯ = 2 / 6
▯ 1 / 3