Question

EXERCISE 8 (1)
1) A committee of 2 boys is to be selected from 4 boys. In how many ways can this be done?​

Answer 1

let 4 boys be b1 b2 b3 b4

S=(b1b2 b1b3 b1b4 b2b3 b1b4 b3b4)

n(S)=6

Answer 2

Answer:

Step-by-step explanation:

Suppose the 4 people are A, B, C, D. So we can pair them in the following ways (without repetition):

A and B,

A and C,

A and D,

B and C,

B and D,

C and D.

So the number of pairs is 6 which is the correct answer! You can use this "ABCD" method for this kind of sums.

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