Math, asked by bhaskarraut777, 8 months ago

* EXERCISE 8.1
1. Solve the following equations:
a. x + 6 = 7
b. 7-4x=8+x
c. x– 6=8 d. x - 1 / 2 = 3
e.x-(-23) =-3 f.32 - x = 71
g. 5 - x= 1+ x h. x - 4 = 3x +31
I.x-3/4=1 j. - 6 – 5x = 7x - 6​

Answers

Answered by finnysamthomas777
3

Step-by-step explanation:

answers are there in the picture go through it ( not sure all of its correct or not)

Attachments:
Answered by ItzCuteboy8
55

Correct Question :-

1. Solve the following equations :-

a) x + 6 = 7

b) 7 - 4x = 8 + x

c) x - 6 = 8

d) x \sf -\frac{1}{2} = 3

e) x - ( - 23) = - 3

f) 32 - x = 71

g) 5 - x = 1 + x

h) x - 4 = 3x + 31

i) x \sf -\frac{3}{4} = 1

j) - 6 - 5x = 7x - 6

Answers :-

a)

\sf x + 6 = 7

:\implies\sf x = 7 - 6

:\implies\boxed{\blue{\bf x = 1}}

b)

\sf7 - 4x = 8 + x

:\implies\sf - 4x - x = 8 - 7

:\implies\sf - 5x = 1

:\implies\sf x = \boxed{\blue{\bf\frac{1}{ - 5}}}

c)

\sf x - 6 = 8

:\implies\sf x = 8 + 6

:\implies\boxed{\blue{\bf x = 14}}

d)

\sf x - \frac{1}{2} = 3

:\implies\sf x = 3 + \frac{1}{2}

:\implies\sf x = \frac{6 + 1}{2}

:\implies\sf x = \frac{7}{2}

:\implies\boxed{\blue{\bf x = 3 \frac{1}{2}}}

e)

\sf x - ( - 23) = - 3

:\implies\sf x + 23 = - 3

:\implies\sf x = - 3 - 23

:\implies\boxed{\blue{\bf x = - 26}}

f)

\sf 32 - x = 71

:\implies\sf - x = 71 - 32

:\implies\sf - x = 39

:\implies\boxed{\blue{\bf x = - 39}}

g)

\sf 5 - x = 1 + x

:\implies\sf - x - x = 1 - 5

:\implies\sf\cancel- 2x = \cancel- 4

:\implies\sf x = \frac{\cancel{4}}{\cancel{2}}

:\implies\boxed{\blue{\bf x = 2}}

h)

\sf x - 4 = 3x + 31

:\implies\sf x - 3x = 31 + 4

:\implies\sf - 2x = 35

:\implies\sf x = \frac{\cancel{35}}{\cancel{ - 2}}

:\implies\boxed{\blue{\bf x = - 17\frac{1}{2}}}

i)

\sf x - \frac{3}{2} = 1

:\implies\sf x = 1 + \frac{3}{2}

:\implies\sf x = \frac{2 + 3}{2}

:\implies\sf x = \frac{\cancel5}{\cancel2}

:\implies\boxed{\blue{\bf x = 2\frac{1}{2}}}

j)

\sf - 6 - 5x = 7x - 6

:\implies\sf - 5x - 7x = \cancel{- 6} \cancel{+ 6}

:\implies\sf - 12x = 0

:\implies\boxed{\blue{\bf x = 12}}

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