Math, asked by kumarmannat2010, 1 month ago

EXERCISE 8(B)
Using the common factor method, find the H.C.F. of:
(0) 16 and 35
(ii) 25 and 20
(iii) 27 and 75
(iv) 8, 12 and 18
(v) 24, 36, 45 and 60
Using the prime factor method, find the H.C.F. of :
(i) 5 and 8
(ii) 24 and 49
(iii) 24,36,45and 60
(iv) 48, 84 and 88
(v) 12, 16 and 28​

Answers

Answered by s15639btrishan08787
5

Answer:

(i) F16 = 1, 2, 4, 8, 16

F35 = 1, 5, 7, 35

Common factors between 16 and 35 = 1

H.C.F. of 16 and 35 = 1

(ii) F25 = 1, 5, 25

F20 = 1, 2, 4, 5, 10, 20

Common factors between 25 and 20 = 1, 5

H.C.F. of 25 and 20 = 5

(iii) F27 = 1, 3, 9, 27

F75 = 1, 3, 5, 15, 25, 75

Common factors between 27 and 75 = 1, 3

H.C.F. of 27 and 75 = 3

(iv) F8 = 1, 2, 4, 8

F12 = 1, 2, 3, 4, 6, 12

F18 = 1, 2, 3, 6, 9, 18

Common factors between 8, 12 and 18 = 1, 2

H.C.F. of 8, 12 and 18 = 2

(v) F24 = 1, 2, 3, 4, 6, 8, 12, 24

F36 = 1, 2, 3, 4, 6, 12, 18, 36

F45 = 1, 3, 5, 9, 15, 45

F60 = 1, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

Common factor between 24, 36, 45 and 60 = 1, 3

H.C.F. of 24, 36, 45 and 60 = 3

Similar questions