- EXERCISE 9.2
The population of a town increases every year by 10% If the present population is 180.000, what wil
be the population of the town after 2 years?
Answers
Answered by
0
Answer:
217,800
Step-by-step explanation:
P×{1+R/100}^2
180000(×(1+10/100)^2
=217,800
Answered by
1
Answer:
2,17,800
Step-by-step explanation:
Given that
Present population = 1,80,000
Increase percentage = 10%
Population after 2 years is
= 1,80,000 × 110/100 × 110/100
= 18 × 110 × 110
= 2,17,800
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