Question

Exercise -
Solve using Urdhwatiryak Vidhi and check the answers:
(3) x-3y
xxty
(1) 4x+1
x x+5
(5) x2+2x+1
(2) 4x+2y
x 3x+3y_
(6) 2x +3y-4
x 3x2+4y+5
* x2+3x+4​

Answer 1

Answer:

3x

3

y

2

×(2x−3y)

=3x

3

y

2

⋅2x−3x

3

y

2

⋅3y

=6x

4

y

2

−9x

3

y

3

Now, for x=−1,y=2, we have

L.H.S.-

3x

3

y

2

×(2x−3y)

=3(−1)

3

(2)

2

(2⋅(−1)−3⋅(2))

=3⋅(−1)⋅4×(−2−6)

=(−12)×(−8)

=96

R.H.S.-

6x

4

y

2

−9x

3

y

3

=6(−1)

4

(2)

2

−9(−1)

3

(2)

3

=6⋅1⋅4−9⋅(−1)⋅8

=24+72

=96

∵ L.H.S. = R.H.S.

Hence verified.