Question

expand (1/4a-1/2b+1)2

Answer 1

Answer:

$Expansion\:of \:(\frac{1}{4a}-\frac{1}{2b}+1)^{2}\\=\frac{1}{16a^{2}}+\frac{1}{4b^{2}}+1\\-\frac{1}{4ab}-\frac{1}{b}+\frac{1}{2a}$

Step-by-step explanation:

$Expansion\:of \:(\frac{1}{4a}-\frac{1}{2b}+1)^{2}$

/* we know the algebraic identity:

$\boxed {(x+y+z)^{2}\\=x^{2}+y^{2}+z^{2}+2xy+2yz+2zx}$*\

=$[(\frac{1}{4a}+(-\frac{1}{2b})+1]^{2}$

=$(\frac{1}{4a})^{2}+(\frac{-1}{2b})^{2}+1^{2}\\+2\times \frac{1}{4a}\times \frac{-1}{2b}+2\times \frac{-1}{2b}\times 1+2\times 1 \times \frac{1}{4a}$

=$\frac{1}{16a^{2}}+\frac{1}{4b^{2}}+1\\-\frac{1}{4ab}-\frac{1}{b}+\frac{1}{2a}$

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Answer 2

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