Question

Expand[1/4a-1/2b+1] whole square

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given,

• $(1/4a -1/2b +1)^2$ is given.

To find,

• We have to expand the given expression.

Solution,

The given expression $(1/4a -1/2b +1)^2$ can be expanded as $1/16 a^2 + 1/4b^2 +1 -1/4 ab -b + 1/2a$.

We can simply expand the given expression by using the following algebraic identity.

          $(a+b+c)^2 = a^2 +b^2 +c^2 +2ab+2bc+2ca$

where a = 1/4a , b = 1/2b, c = 1

Substituting the values of a, b, and c in the above algebraic identity, we get

                       $= (1/4a)^2 +(-1/2b)^2 +(1)^2 + 2(1/4a)(-1/2b) + 2(-1/2b) (1) + 2(1)(1/4a)$

$= 1/16 a^2 + 1/4b^2 +1 -1/4 ab -b + 1/2a$

Hence, the given expression $(1/4a -1/2b +1)^2$ can be expanded as $1/16 a^2 + 1/4b^2 +1 -1/4 ab -b + 1/2a$.