Question

expand (2a-3b)^3 using suitable

Answer 1

Answer:

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We need to expand (2a−3b)3

We know suitable identity is (x−y)3=x3−3x2y+3xy2+y3

Here x=2a and y=3b

Therefore, value of (2a−3b)3 is

=(2a)3−3(2a)2(3b)+3(2a)(3b)2−(3b)3

=8a3−36a2b+54ab2−27b3

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Answer 2

Answer:

(2a-3b) ³

(2a)³- (3b) ³-3.(2a)².3b+ 3.2a.(3b) ²

8a3 -27b3 - 36(a) ²b + 54a(b) ²

Step-by-step explanation:

This is the answer.. hope you understand it well