Question

Expand (2a_3b)³using appropriate identities​

Answer 1

Answer:

It is in the form ( a - b )³.

(a-b)³=a³-3a²b+3ab²-b³

( 2a - 3b ) ³ = (2a)³ - 3×(2a)²×3b + 3×2a×(3b)² - (3b)³

= 8a³ - 36a²b + 54ab² - 27b³

Hope this will help you.

Answer 2

Step-by-step explanation:

This equation is in the form (a-b)^3

=a^3-b^3-3ab(a-b)

So when you put the values in the above identity u get

8a^3-27b^3-18ab(2a-3b)

I hope you understood