Question

expand (2a+3b+4c)square.... ... ..​

Answer 1

Here the sum is (2a+3b+4c)^2

for this the formula is (a+b+c)^2 = (2a)^2+(3b)^2+(4c)^2+2(2a)(3b)+2(3b)(4c)+2(4c)(2a)

   solution =                     4a^2+9b^2+16c^2+12ab+24bc+16ac

           

pls mark as brainlist answer pls.                                         

Answer 2

Step-by-step explanation:

(p+q+r)^2=p^2+q^2+r^2+2pq+2qr+2rp

now

we have to find (2a+3b+4c)^2

(2a+3b+4c)^2

=(2a) ^2+(3b) ^2+(4c) ^2+2(2a)(3b) +2(3b)(4c) +2(2a)(4c)

=4a^2+9b^2+16c^2+12ab+24bc+16ac