Question

If ANYONE answer to this question
I'll mark them as the BRAINLIEST
(if it is correct ;))
9. From the top of a house, h metres high from the ground, the angles of elevation and depression of the top and bottom of a tower on the other side of the street are 'A' and 'B'
respectively. Prove that the height of the tower is h (1 + tanA cotB). [AI CBSE, 2006, 2007]​

Answer 1

Answer:

The height of the opposite house is h(1+tanα.cotβ) metres

Step-by-step explanation:

Step 1:

Let B be the window of a house AB and let CD be the other house. Then, AB= EC =h metres.

Let CD = H metres. Then, ED= (H-h) m

Step 2:

In ∆BED,

cotα = BE/ED

BE = (H-h) cotα ... (a)

In ∆ACB,

Step 3:

AC/AB = cotβ

AC=h.cotβ …. (b)

But BE=AC

Step 4:

(H-h) cotα = hcotβ

Step 5:

H = h(1+tanα cotβ)  

Answer 2

Answer:

Refer the attachment dear....!!!

Step-by-step explanation:

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