Expand (-2a-b+3c) to the whole square Plz tell me answer I am in trouble with this question
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Answered by
20
Step-by-step explanation:(-2a-b+3c)(-2a-b+3c)
= -2a(-2a-b+3c) -b(-2a-b+3c) +3c(-2a-b+3c)
= 4a^2 +2ab-6ac+ 2ab+b^2-3bc- 6ac-3bc+9c^2
= 4a^2+b^2+9c^2 + 4ab -12ac-6bc
Answered by
14
Step-by-step explanation:
Step-by-step explanation:(-2a-b+3c)(-2a-b+3c)
= -2a(-2a-b+3c) -b(-2a-b+3c) +3c(-2a-b+3c)
= 4a^2 +2ab-6ac+ 2ab+b^2-3bc- 6ac-3bc+9c^2
= 4a^2+b^2+9c^2 + 4ab -12ac-6bc
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