Question

expand (2x-1÷x)(3x+2÷x)

Answer should be 6x^2+1-2/x^2
Wrong explanation and spammers will be strictly reported

Answer 1

Answer:

The correct answer with steps are in the image attached to this answer.

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Answer 2

$\Large{\underline{\underline{\bf{Solution :}}}}$

$\Large{\underline{\underline{\bf{Given :}}}}$

$\sf{\frac{2x - 1}{x} \times \frac{3x + 2}{x}}$

$\rule{200}{1}$

$\Large{\underline{\underline{\bf{To \: Find :}}}}$

★ We have to find the value of,

$\sf{\frac{2x - 1}{x} \times \frac{3x + 2}{x}}$

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$\Large{\underline{\underline{\bf{Explanation :}}}}$

For expanding the above question firstly, we will multiply both the denominator s

$\sf{\rightarrow \frac{2x - 1}{x} \times \frac{3x + 2}{x}} \\ \\ \sf{\rightarrow \frac{(2x - 1)(3x + 2)}{x^2}} \\ \\ \bf{Now,}$

We will multiply (2x) by (3x and 2). Then we will multiply (-1) by (3x and 2).

$\sf{\rightarrow \frac{6x^2 + 4x - 3x - 2}{x^2}}$

Now, we will add or subtract 4x and 3x

$\sf{\rightarrow \frac{6x^2 + x - 2}{x^2}} \\ \\ \Large{\implies{\boxed{\boxed{\sf{\frac{6x^2 + x - 2}{x^2}}}}}} \\ \\ \sf{\therefore \: \frac{6x^2 + x - 2}{x^2} \: is \: correct \: answer.}$