expand (2x-3y)³ by using suitable identity
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Answer:
8x^3 - 27y^3 - 36 x^2y + 54 xy^2
Step-by-step explanation:
from (a - b)^3 = a^3 - b^3 - 3ab ( a - b )
(2x-3y)³= (2x)^3 - (3y)^3 - 3* 2x * 3y (2x - 3y)
= 8x^3 - 27y^3 - 18 xy (2x - 3y)
= 8x^3 - 27y^3 - 36 x^2y + 54 xy^2
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