expand :- (2x+3y+4z)²
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We solve the given expression (2x+3y+4z)2 as shown below:
(2x+3y+4z)2
=(2x)2+(3y)2+(4z)2+(2×2x×3y)+(2×3y×4z)+(2×4z×2x)
(∵(a+b+c)2=a2+b2+c2+2ab+2bc+2ca)
=4x2+9y2+16z2+12xy+24yz+16zx
Hence, (2x+3y+4z)2=4x2+9y2+16z2+12xy+24yz+16zx.
hope this HELPS you
i am expert in MATHEMATICS physics and chemistry
Answered by
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(2x – 3y + 4z)^2 = 4x^2 + 9y^2 + 16z^2 - 12xy - 24yz + 16zx.
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