expand (3a+2b+c)² expand this please
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Expand:(3a−2b+5c)
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We have (x+y+z)
2
=x
2
+y
2
+z
2
+2(xy+yz+zx)
Take x=3a,y=−2b and z=5c
(3a−2b+5c)
2
=(3a)
2
+(−2b)
2
+(5c)
2
+2(3a×−2b+(−2b)×5c+5c×3a)
=9a
2
+4b
2
+25c
2
+2(−6ab−10bc+15ac)
=9a
2
+4b
2
+25c
2
−12ab−20bc+30ac
∴(3a−2b+5c)
2
=9a
2
+4b
2
+25c
2
−12ab−20bc+30ac
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