Question

expand (3a-b+2c)^2 ​

Answer 1

Step-by-step explanation:

$(3a - b + 2c)^{2}$

$= (3a + (- b) + 2c)^{2}$

$= (3a )^{2} + ( - b) ^{2} + (2c) ^{2} + 2(3a)( - b) + 2( - b)(2c) + 2 (3a)(2c)$

$using \: identity \: (a + b + c) ^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ac$

$= 9a^{2} + {b}^{2} + 4 {c}^{2} - 6ab - 4bc + 12ac$

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