Question

the nature of roots of quadratic equations x2-5x - 7 are real and equal ​

Answer 1

Answer:

Step-by-step explanation:

x² - 5x - 7 = 0

D = b² - 4ac = (-5)² - 4(1)(-7) = 25 + 28 = 53

$x_{12}$ = (- (-5) ± √D) / 2

$x_{1}$ = (5 + √53)/2 ≈ 6.14

$x_{2}$ = (5 - √53)/2 ≈ - 1.14

Answer 2

Answer:

False

Step-by-step explanation:

Nature of roots of any quadratic equation is determined by the value under root or discriminant of that equation.

Discriminant of ax² + bx + c = 0 is b²- 4ac.  On comparing:

a = 1,   b = -5,   c = - 7

∴ discriminant = (-5)² - 4(1)(-7)

                        = 25 + 28

                        = 53

As the discriminant > 0, roots are real and irrational(and different).

Roots are real but not equal