Question

Expand (3a+b-3c) ^2​

Answer 1

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$(3a + b - 3c)^2$

= $(3a + b - 3c)(3a + b - 3c)$

= $9a² + b² - 9c²$

Answer 2

Answer:

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Step-by-step explanation:

→ Formula to be used :

→ (a + b - c)² = a² + b² + c² + 2ab - 2bc - 2ca

→ (3a)² + (b)² + (-3c)² + 2(3a)(b) - 2(b)(-3c) - 2(-3c)(3a)

→ 9a² + b² + 9c² + 6ab + 6bc + 18ca