Expand (3x-2y)² using identity 4
Answers
Answered by
0
ANSWER
(4x−2y−3z)2
We know that (x+y+z)2=x2+y2+z2+2xy+2yz+2xz
Here x=4x, y=-2y and z=-3z we get
(4x−2y−3z)2=(4x)2+(−2y)2+(−3z)2+2(4x)(−2y)+2(−2y)(−3z)+2(4x)(−3z)
=16x2+4y2+9z2−16xy+12xy−24xz
(4x−2y−3z)2
We know that (x+y+z)2=x2+y2+z2+2xy+2yz+2xz
Here x=4x, y=-2y and z=-3z we get
(4x−2y−3z)2=(4x)2+(−2y)2+(−3z)2+2(4x)(−2y)+2(−2y)(−3z)+2(4x)(−3z)
=16x2+4y2+9z2−16xy+12xy−24xz
Similar questions