Question

expand (4x+3y)² .....................​

Answer 1

$\left(4x+3y\right)^2$

$\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2$

$a=4x,\:\:b=3y$

$=\left(4x\right)^2+2\cdot \:4x\cdot \:3y+\left(3y\right)^2$

$=16x^2+24xy+9y^2$

Answer 2

AnSwEr-:


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16 x^2 + 24 xy + 9y^2

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Given ,

Equation-: (4x+3y)²

To find ,


We have to expand the equation

Solution-:

(4x + 3y)^2 =

Using identity
-:

(a+ b)^2 = a^2 + 2ab + b^2

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(4x + 3y)^2 = (4x)^2 + 2 (4x)(3y) + (3y)^2

= 16 x^2 + 24 xy + 9y^2

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Final answer-:

16 x^2 + 24 xy + 9y^2

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Some identities :

1: (a – b)^2 = a^2 – 2ab + b^2

2: (a+ b)^2 = a^2 + 2ab + b^2

3: a^2 – b^2= (a + b)(a – b)


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